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How do you solve 2xplus 1 over 3x equals xminus 1 over 5x?
Victoriano05
one way to solve an equation in this format, "a/b = c/d", is to multiply both sides by "b"and by "d". You're effectively "cross multiplying" the fractions:
(2x + 1) / 3x = (x - 1) / 5x ∴(2x + 1)(5x) = (x - 1)(3x) ∴10x2 + 5x = 3x2 - 3x
You can then factor an "x" out of both sides
∴10x + 5 = 3x - 3
And rearrange to solve:
∴10x - 3x = -3 -5 ∴7x = -8
∴x = -8/7
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∙ 14y ago
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