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Q: How do you solve 2xsquared -9x equals 18?

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2x2 - 9x = 18 2x2 - 9x -18 = 0 (2x - 18)(x + 9) x= -9 and 9

9x+18 = 180 9x = 180-18 9x = 162 x = 18

1/9=x/18 18=9x 2=x

44 = 9x +8 36=9x 4=x

9 x 27 equals 243

2y - 9x = 14 2y = 14 + 9x y = (14 + 9x) / 2

x = -3

Fsxjugfxbi

11x = 20x +1811x-20x=18x(11-20)=18-9x=18x=-2

You can solve that equation for either x or y. To solve for y: Subtract 9x from both sides to get -4y=7-9x Divide both sides by -4 to get y=-(7-9x)/4 or -1.75+2.25x

9x+6 = 7x+18 9x-7x = 18-6 2x = 12 x = 6

9x-5x=4x, 7/4=1.75, x=1.75

Divide both sides of the equation by x: x2 = 9x x2 / x = 9x / x x = 9

2x+3=9x =>3=7x =>3/7=x

9x + y = 22to solve for x-subtracy y from both sides --> 9x = 22 - ydivide by 9 on both sides --> x = (22/9) - (y/9)to solve for y - subtract 9x from both sides --> y = 22 - 9x

-9x + 4 = -50 -9x = -50 - 4 -9x = -54 -x = -6 x = 6.

8x+9=9x-18+9 = 8x+9=9x-9 = 1x=0 (:

2x + 5x - 1 = 9x 7x - 1 = 9x -1 = 9x - 7x -1 = 2x -1/2=x

10x=x 9x=0 x=0

2x+3 = 9x 3 = 9x-2x = 7x 7x = 3 x = 3/7

It is not possible to give a sensible answer because the operator between y1 and 9x is not visible.

9x - 20 = 61 Add 20 to both sides: 9x = 81 Divide both sides by 9: x = 9

2x2 - 9x + 3 = 0 Using the quadratic formula: x = [9 Â± sqrt(92 - 4*2*3)]/(2*2) = [9 Â± sqrt(81-24)]/4 = [9 Â± sqrt(57)]/4 = 0.36254 or 4.13746 (to 5 dp)

9x + 3y = -54 3y = -9x - 54 y = -(3x + 18) Therefore, the y-intercept of this equation is y=-18.

x - 10x = 9x, so 9x + 3 = 0, so 9x = -3 so x = -1/3