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If you graph it, you will find there is only one real root at approx x = -0.868145.

The other 2 roots are complex numbers. I don't remember the steps, to get that.

Q: How do you solve 34x3-x2 plus 23?

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23

w + 23w = 24w

-4x+3 = 23+6x -4x-6x = 23-3 -10x = 20 x = -2

h + 23 = 32 Subtract 23 from both sides: h = 32 - 23 = 9

X = 12

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68

It does not help you.

23

w + 23w = 24w

-4x+3 = 23+6x -4x-6x = 23-3 -10x = 20 x = -2

h + 23 = 32 Subtract 23 from both sides: h = 32 - 23 = 9

X = 12

15+b = 23 Subtract 15 from both sides b = 8

By including its plus or minus signs

Can you help with this equation? Thanks. Solve for x and y and z for the following. x plus y plus z equals 9 x plus 2y plus 3z equals 23 x plus 5y plus -3z equals -7

Solve this system of equations. 5x+3y+z=-29 x-3y+2z=23 14x-2y+3z=-18 Write the solution as an ordered triple.

Collect the like terms;42x-23 = 940Add 23 to both sides;42x = 963Divide both sides by 42;x = 963/42