If: 3x+8 = 14
Then: 3x = 14-8
So: 3x = 6
Divide both sides by 3: x = 2
-3x+14 = -4 -3x = -4-14 -3x = -18 x = 6
3x+5=14 3x=9 x=3
solve -3x-3y=-15
3x + 2x = 5x. 5x= (-4) X = (-4)/5 x= -0.8
4 + 3x = -8subtract four from each side3x = -12divide each side by threex = -4
x = 6
balance the equation 3x-x=20-6 3x-x=2x 20-6=14 2x=14 x=7
-3x+14 = -4 -3x = -4-14 -3x = -18 x = 6
3x + 7y = 14Subtract 3x from each side:7y = -3x + 14Divide each side by 7:y = -3/7 x + 2
3
x = -8
23
x=7
Can you clarify the question please? Is it (14 x 2)-1 + (1x-1) = 3x+1?
x2 plus 3x plus 3 is equals to 0 can be solved by getting the roots.
3x plus 5 equals 20: 3x + 5 = 20 3x + 5 - 5 = 20 - 5 3x = 15 3x/3 = 15/3 x = 5
-3x + 5 = 20 -3x = 15 x = -5