That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (1 plus or minus the square root of 29) divided by 2
x = 3.192582403567252
x = -2.192582403567252
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (7 plus or minus the square root of 17) divided by 2.
x = 5.561552812808831
x = 1.4384471871911697
That doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: 1 plus or minus i times the square root of 6.
x = 1 + 2.449489742783178i
x = 1 - 2.449489742783178i
where i is the square root of negative 1.
Add 1 to both sides.
7x2 - 8x + 1 = 0 factors to (x - 1)(7x - 1)
x = 1, 1/7
Check it.
7 - 8 + 1 = 0
7/49 - 56/49 + 49/49 = 0
It checks.
That depends on what you want to do with them.
-7 x 8 x -1 = 56
-7 + 8 + -1 = 0
-7 - 8 - -1 = -14
There are other possibilities.
Multiply both sides by 7.
-35 = -19 - x
Add 19 to both sides.
-16 = -x
Multiply both sides by -1.
x = 16
x2 + 7x - 8; since -8 = (8)(-1) and 8 - 1 = 7
= (x + 8)(x - 1)
-((x + 8)(x - 1))
(3x - 4)(x - 1)
2/7x = 8x = 8 x 7/2x = 28
(5x - 3)(x + 8)
(x + 5)(x + 8)
(x + 4)(x + 8)
(7x - 8)(2x - 7)
(7x + 8)(7x - 8)
7x+8
7x + 8 = 10x - 2 ∴ 3x = 10 ∴ x = 10/3
56x^2 + 96x + 40
5x-8 + 7x 12x-8 12x = 8 x = 8/12 x= 2/3
x(7x ^2 - 4x + 8)
7x+8=2 .....-8..-8 7x=-6 7x/7=6/7 x=6/7 In conclusion, 7(6/7)+8=2 I'm sure you meant: x = - (6/7) or -6/7 (not 6/7).
4x + 8 + 7x + 12 = 11x + 20
x=1
7x + y = 8 Subtract 7x from each side of the equation: y = -7x + 8
(7x + 8)(7x - 9)