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Q: How do you solve 7x plus 2 equals 16?

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40 -7x = -16 -7x = -16 -40 -7x = -56 x = 8

7x + 2 = 5,6

Subtract by 7x and divide by 2.

7x + y = 4y = 4 - 7x

24

3x+5=7x-11 5=4x-11 4x=16 x=4

7x + y = 8 Subtract 7x from each side of the equation: y = -7x + 8

x=6

7x + 16 = 3x + 4 4x = -12 x = -3

There is no symbol between 7x and 31. Please resubmit using words eg "plus", "equals" etc.

7x = 3x - 12 4x=-12 x=-3

(3,3)

i will simplify: 5 times x times 6= 7 times x - 16

4x+9 = 7x+3 4x-7x = 3-9 -3x = -6 x = 2

-7x + 6 + 7x - 2 = 4

7x + 8 = 11x + 3, solve for xsubtract 7x from both sides8 = 11x - 7x + 38 = 5x + 3subtract 3 from both sides5 = 5xdivide both sides by 51 = x.

x2+7x+12

(0,2)

x=4 x=0

2x+3 = 9x 3 = 9x-2x = 7x 7x = 3 x = 3/7

7x+6 = -3x-24 7x+3x = -24-6 10x = -30 x = -3

sin7x-sin6x+sin5x

7x-4=x+2 7x=x+2+4 7x=x+6 7x-x=6 6x=6 X=1

7X + 2Y = 10 - 7X + Y = - 16 -----------------------just add 3Y = - 6 Y = - 2 --------------find X, top equation 7X + 2(- 2) = 10 7X - 4 = 10 7X = 14 X = 2 ------------check both original equations for consistency; top first 7(2) + 2(- 2) = 10 14 - 4 = 10 10 = 10 ------------top checks; now check bottom equation - 7(2) - 2 = - 16 -14 - 2 = - 16 - 16 = - 16 ------------------both check and are then consistent

If: x+3+6x+9 = 0 then 7x+12 = 0 So: 7x = -12 and x = -12/7