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1. Just take a root. ex x3= 216

x = cube root 216

x = 6

2. Factoring if possible. ex x2 + 4x - 5 = 0

(x+5)(x-1)= 0

x = -5 and x = 1

3. other types of these require lots of guided guessing from andanced math courses.

4. the exponent is the variable. use logarithms

ex 3x = 5

x ln3 = ln 5

x = (ln 5)/(ln 3)

OF COURSE some alg might need to be used to rearrange the equations to get them to look like the examples.

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Q: How do you solve a problem containing an exponent?
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