Amperes measure the rate of flow of electricity in a conductor Volts measure electrical pressure Watts measure the amount of energy or work that can be done by Amperes and Volts Relationship: Work = Pressure x Flow or Watts = Volts x Amperes When you know two variables you can calculate the other Formulas - This formula referred to as the West Virginia Formula (W - VA)
Watts = Volts x Amps Volts = Watts / Amps Amps - Watts / Volts Refer to link below for more information
watts = current * volts
current = watts / volts
Current is inversely proportional to resistance. If you double the resistance, you halve the current. Ohm's Law: Volts = Amps * Ohms Solve for Amps: Amps = Volts / Ohms
Ohm's Law states Voltage = Current x Resistance. You rewrite the equation as Current = Volts / Resistance to solve for current.
I(current) = V(voltage)/R(resistence) Example : 220 V / 5000 Ohm = 0.044 A (Ampère) = 44mA
What you are talking about is the electrical potential, or voltage, necessary to produce a current of 4 amps through a material with a resistance of 3 ohms. The typical way to solve such a problem is by using Ohm's Law, stating that the current produced is proportional to the potential across the resistor but inversely proportional to the resistance. In other words, I = V / R, where I is the current in amps, V is the electrical potential in volts, and R is the resistance in ohms. Here we know R and I, so we rearrange this equation to get V by itself: V = I * R. So, to get the answer, multiply your 4-amp current by your 3-ohm resistance, and you will get 12 volts.
You need a regulator.
Current is inversely proportional to resistance. If you double the resistance, you halve the current. Ohm's Law: Volts = Amps * Ohms Solve for Amps: Amps = Volts / Ohms
Ohm's Law states Voltage = Current x Resistance. You rewrite the equation as Current = Volts / Resistance to solve for current.
The resistance of a lamp operating at 115 volts and using 0.25 amp of current is 460. The relationship I used is Ohm's law.
I(current) = V(voltage)/R(resistence) Example : 220 V / 5000 Ohm = 0.044 A (Ampère) = 44mA
What you are talking about is the electrical potential, or voltage, necessary to produce a current of 4 amps through a material with a resistance of 3 ohms. The typical way to solve such a problem is by using Ohm's Law, stating that the current produced is proportional to the potential across the resistor but inversely proportional to the resistance. In other words, I = V / R, where I is the current in amps, V is the electrical potential in volts, and R is the resistance in ohms. Here we know R and I, so we rearrange this equation to get V by itself: V = I * R. So, to get the answer, multiply your 4-amp current by your 3-ohm resistance, and you will get 12 volts.
You need a regulator.
Zero volts produces zero current.
12 volts DC current except the current to the spark plugs which can be 12,000 volts up to as much as 45,000 volts.
the volts are 230
In the U.S. 120 volts. <<>> Using the equation E = I x R, Volts = Amps x Resistance = 110 volts.
To solve this problem, we use the definition of power. Power is measured in watts and is defined as P = V x I, where P is power (Watts), V is voltage (Volts) and I is current (Amps). Solving this equation for I, we get I = P / V. Using the SI prefixes "kilo"=1,000 and "Mega"=1,000,000 we can establish that 14.1kV = 14,100V and 32.7MW = 32,700,000W. Thus, I = (32,700,000 / 14,100) = 2319.1 Amps.
Use the formula P= VI (power = potential x current) where (watts = volts x amps). The current I in amperes is equal to the watts divided by the volts, 40/120. The bulb is using 1/3 amp of current.