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How do you solve for x in the equation 3 over x square plus 3 over 4x minus 3 over 1 equals 6 over 2x square minus 6 over 3x plus 6 over 5?
Wiki User
∙ 13y ago
3/(x2+4x-1) = 6/(2x2-3x+5)
Cross - multiply in order to eliminate the fractions:
6*(x2+4x-1) = 3*(2x2-3x+5)
6x2+24x-6 = 6x2-9x+15
6x2-6x2+24x+9x = 15+6
33x = 21
x = 21/33 => x = 7/11
Wiki User
∙ 13y ago
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