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There are 5 ways to solve a system.
The most popular is to write both in standard notation then add the equations together. The easiest to explain is to use substitution. Solve one for one of the variables then substitute in the other equation.
The other ways to solve are to use graphing and find the intersection. Determinants and matrices are the other two ways.
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How can variables be used to help solve a math problem?
If you don't know something in a math equation you can replace it with a variable and then solve it algebraically.
How do you find the volume of a cylinder with just the volume and the height?
No matter what you're finding, use the equation V=πr2h. Then solve algebraically. V=volume h=height r=radius πr2=area of the base
Solve this equation for A A divides 2 equals 4?
Written algebraically, the equation is (2/A)=4.The first step is to move the variable A from the denominator. To do this, multiply both sides of the equation by A:A*(2/A)=4*AThe A in the denominator on the left is canceled out and we are left with:2=4*ATo solve for A divide both sides of the equation by 4:2/4=ATwo over four simplifies to one half, which equals A:1/2=A
What do you call the solution of a equation derived from an original equation that is not a solution of the original equation?
That's an extraneous solution. You need to check for these when algebraically solving equations, especially when you take both sides of an equation to a power.
What are some ways to solve an equation?
solve it
How can variables be used to help solve a math problem?
If you don't know something in a math equation you can replace it with a variable and then solve it algebraically.
How do you solve for the indicated variable?
Algebraically manipulate the equation until you have the indicated variable on one side of the equation and all of the other factors on the other side.
Which step would not be a possible first step for solving the following equation algebraically?
The first step not possible in solving an equation algebraically is not to provide an equation in the first place in which it appears to be so in this case.
How do you find the volume of a solid if you only have the surface area?
It depends on if the item is a cylinder, block, or pyramid. You would replace the appropriate geometric equation variables and solve for the unknown algebraically.
What are the advantages of solving a graphical equation algebraically?
You get the exact solution.
How do you find the volume of a cylinder with just the volume and the height?
No matter what you're finding, use the equation V=πr2h. Then solve algebraically. V=volume h=height r=radius πr2=area of the base
Solve this equation for A A divides 2 equals 4?
Written algebraically, the equation is (2/A)=4.The first step is to move the variable A from the denominator. To do this, multiply both sides of the equation by A:A*(2/A)=4*AThe A in the denominator on the left is canceled out and we are left with:2=4*ATo solve for A divide both sides of the equation by 4:2/4=ATwo over four simplifies to one half, which equals A:1/2=A
Can you solve for a variable in an equation?
Sure. You can always 'solve for' a variable, and if it happens to be the only variable in the equation, than that's how you solve the equation.
Do you answer an equation?
you don't answer an equation, you solve an equation
What do you call the solution of a equation derived from an original equation that is not a solution of the original equation?
That's an extraneous solution. You need to check for these when algebraically solving equations, especially when you take both sides of an equation to a power.
The point-slope equation for a given line may look different than the slope- intercept form but they will simplifly algebraically to the same equation?
True ~APEX
How do you solve systems by using the substitution method?
You solve one of the equation for one of the variables. For example, if the variables involved are "x" and "y", you might solve for "y". It doesn't really matter what variable you solve for first, so you can solve for whatever variable is easiest to solve. Then - assuming you got, for example, "y = 3x -1", in this example you would replace every "y" by "3x - 1" in the other equation or equations.
