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If you factor this you would first factor out a common multiple
4(c^2+3c-18)
4(c+6)(c-3)
The 6 and -3 were arrived by thinking,"What adds together to get +3 and mu;tiplies to get -18?"
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How do you simplify 4c2 plus 5c plus 2c?
4c2 + 5c + 2c = 4c2 + 7c = c(4c + 7)
What is 24c3 plus 375z3 factored completely?
24c3 + 375z3 = 3*(8c3 + 125z3) = 3*(2c + 5z)*(4c2 - 10cz + 25z2)
How do you factor this binomial 24cĀ² plus 96c plus 90?
24c2 + 96c + 90 = 6*(4c2 + 16c + 15) = 6*(2c + 3)*(2c + 5)
How do you solve 4 cosine squared x - 2 equals 0?
Let c represent cos x. Then, we have, 4c2 - 2 = 0; whence, 4c2 = 2, c2 = ½, and c = ±√½ = ±½√2; that is, cos x = ±½√2. From this, it is evident that, for 0 ≤ x < 360°, x = 45°, 135°, 225°, or 315°; or, if you prefer, for 0 ≤ x < 2π, x = ¼π, ¾π, 1¼π, or 1¾ π.
How do you solve 4y plus x equals 8?
How do you solve 4y plus x equals 8
How do you simplify 4c2 plus 5c plus 2c?
4c2 + 5c + 2c = 4c2 + 7c = c(4c + 7)
What is the value of 4C2?
6
What is 24c3 plus 375z3 factored completely?
24c3 + 375z3 = 3*(8c3 + 125z3) = 3*(2c + 5z)*(4c2 - 10cz + 25z2)
How do you factor this binomial 24cĀ² plus 96c plus 90?
24c2 + 96c + 90 = 6*(4c2 + 16c + 15) = 6*(2c + 3)*(2c + 5)
How do you solve 4 cosine squared x - 2 equals 0?
Let c represent cos x. Then, we have, 4c2 - 2 = 0; whence, 4c2 = 2, c2 = ½, and c = ±√½ = ±½√2; that is, cos x = ±½√2. From this, it is evident that, for 0 ≤ x < 360°, x = 45°, 135°, 225°, or 315°; or, if you prefer, for 0 ≤ x < 2π, x = ¼π, ¾π, 1¼π, or 1¾ π.
How do you solve 4y plus x equals 8?
How do you solve 4y plus x equals 8
Factorization of b4 -16b2c2 - 80 c4?
(b2 - 20c2)(b2 + 4c2)
B equals 10 plus a solve for a?
Not enough information to solve
How do you solve a equals b plus c plus d solve for c?
If: a = b+c+d Then: c = a-b-d
How to solve x plus y for graphing?
You cannot solve x plus y since that is an expression, not an equation (nor inequality).
What is the product to 4C 2nd power times -2CD 2nd power?
4C2 * (-2CD2) = -8C3D2
How do you solve 5x plus 30?
There's nothing to solve, it's simply an expression.
