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Q: How do you solve this a squared minus b squared plus ac minus bc?

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(b-c)(a+b)-ac

6(b - ac + b2 - bc)

6(ab - ac + b2 - bc)

carry the six then use the quadratic formula negative b plus or minus the squrare root of b squared minus 4 ac all over 2

The most surefire way to find the zeroes of a quadratic are to apply the quadratic formula. The formula says that the zeroes of quadratic equations which are generally written as ax2+bx+c=y can be found by taking (-b+/-(b2-4ac).5)/2a or if this notation makes no sense... negative b plus or minus the square-root of b squared minus four ac all over two a. Note: if b squared minus four ac is less than zero, the function has non-real roots

negative b plus or minus the square root of b minus 4 times ac all over 2 a

this is what you would: 4x+6=3x-1 -6 -6 ---- 4x=3x-7 -3x -3x ---- 1x=-7 ---- x=-7

it means like ac angle or a squared like in the phythangren theorem its a squared + b squared = c squared

Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc. And using ^ to indicate powers (eg x-squared = x^2).

The square root of 149 (7 squared plus 10 squared equals 149).

y=mx+b A=xy; A=(pi)r^2; V=xyh; (-b= or - (b^2-4ac)^1/2)/2a ( actually read as negative b plus or minus the square root of b squared minus four ac, all divided by 2a....quadratic formula) This should get you, if you need more or this is not what you were looking for, let me know.

DC? reverse the plus and minus connection AC? look for jumpers in the wire connection area for field jumper reverse lugs

ab x ac = ab - ac

Diodes convert AC into DC by allowing current flow in one direction only. Since AC is alternating between plus and minus it is not possible to use a diode to allow AC to flow in one direction and not in the other direction.

A bridge will conduct current whenever there is voltage present regardless of AC polarity as minus or plus therefore the name full wave rectifier.

Well. Multiply both sides by 'c'. After that you should have something like ac=b-4 then you add 4, to get this result 4+ac=b.

yes because ab plus bc is ac

The diameter of aluminum wires will be 85 mm squared and copper wires will be 127 mm squared for AC current 200 amp.

ac + cb = ab = 9 2x - 1 + 3x = 9 5x -1 = 9 So 5x = 10 Thereby x =2. Also ac = 3 and cb = 6

In a right angled triangle its hypotenuse when squared is equal to the sum of its squared sides which is Pythagoras' theorem for a right angle triangle.

If you put a diode in series with an AC sine wave that goes plus and minus, it will cut off either the positive or negative portion of the waveform, depending on the direction of the diode in circuit. So in effect you have a pulse equal to one half cycle of the sine wave.

If you mean (a-b+c)^2, then... a^2 - ab + ac - ab + b^2 - bc + ac - bc + c^2 = a^2 + b^2 + c^2 - 2ab + 2ac - 2bc.

If you have two straight lines AB and BC such that the two lines meet at B and AB and BC make 90 degrees with each other then the pythagorean theory (theoram) states that the length of line AC (assume that points A and C are joined by a straight line) then (AC) squared = (AB) squared +(BC) squared

you use Pythagoras theorem. Square of the Hypotenuse = square of the other 2 sides i.e ac squared = ab squared + bc square = 22 Squared + 32 Squared = 484 + 1024 = 1508 so ac = square root of 1508 = 38.83 cm(2 d.p)

A+BC+AC+B=A+BC+AC+B unless any of these variables has an assigned value.