7X + 2Y = 10
- 7X + Y = - 16
-----------------------just add
3Y = - 6
Y = - 2
--------------find X, top equation
7X + 2(- 2) = 10
7X - 4 = 10
7X = 14
X = 2
------------check both original equations for consistency; top first
7(2) + 2(- 2) = 10
14 - 4 = 10
10 = 10
------------top checks; now check bottom equation
- 7(2) - 2 = - 16
-14 - 2 = - 16
- 16 = - 16
------------------both check and are then consistent
a2+30a+56=0 , solve for a Using the quadratic formula, you will find that: a=-2 , a=-28
-2 plus 5 equals +3
If: a = b+c+d Then: c = a-b-d
you can not solve this equation
b = y - mx.
By elimination: x = 3 and y = 0
(2,-2)
You cannot solve one linear equation in two variables. You need two equations that are independent.
Yes and it works out that x = 3 and y = 4
y=16 x= -4
The elimination method only works with simultaneous equations, hence another equation is needed here for it to be solvable.
No. Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution.
16
The answer is that it cannot be done. To solve a set of equations in k variables (in this case, 2) you need at least two independent equations.
The given expression can't be solved as equations because there are no equality signs.
Solve using the quadratic formula
How do you solve 4y plus x equals 8