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Q: How do you solve x 2 and x 5?

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You fill in for x and solve the equation3(5)^2 - 2(5)15^2 - 10; now solve

2 x 2 x 5 x 11

8

x - 5 = 2, we can solve for x by adding 5 to both sides yielding: x = 7

To solve for x: x2 = 5x + 2 x2 - 5x = 2 x2 - 5x + (5/2)2 = 2 + (5/2)2 (x - 5/2)2 = 8/4 + 25/4 x - 5/2 = ± √(33/4) x = (5 ± √33) / 2

2

If you mean: 5+2(x-1) = 12 then the value of x works out as 4.5

x+3y=2 x= -5 y = 1

(x+5)^2 and therefore x = -5

If you mean 2(x+5) + (3*5) then it can be simplified to: 2x+25

X squared - 3x - 10 = 0 (x-5) (x+2) = 0 x - 5 = 0 x + 2 = 0 X= 5 x = -2

x/5 = 2/10 Cross multiply to solve for x. 10x=10. x=1.

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