Q: How do you solve x plus 3 plus 2x equals x plus 9?

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3

2x+3 = 7 2x = 7-3 2x = 4 x = 2

2x+3 = 9x 3 = 9x-2x = 7x 7x = 3 x = 3/7

4x + 3 = -3 + 2x + 14 2x + 3 = -3 +14 2x + 3 = 11 2x = 8 x=4

2x+3 = -11 2x = -11-3 2x = -14 x = -7

2x+3=9x =>3=7x =>3/7=x

3x+4 = 2x-3 3x-2x = -3-4 x = -7

2x + 3 = x 2x + 3 - 3 = x - 3 2x = x - 3 2x - x = x - 3 - x x = -3

2x + 3 = 9x Subtract 2x from both sides: 3 = 7x Divide both sides by 7: 3/7 = x

x = 3 and y = 3 Form a simultaneous equation and solve by elimination.

(3,3)

If 2x + 5 = 11, then 11 - 5 = 2x 6 = 2x 3 = x

3x-2 = 2x+3 3x-2x = 3+2 x = 5

2x + 2/3= 5/3 2x= 3/3 2x=1 x=1/2

2x + 3 = 9 To solve Subtract '3' from both sides 2x = 6 Divide both sides by '2' x = 3 The Answer!!!!!

2x + 3y = 9x = 3, y = 1 therefore 6 + 3 = 9

2x/3 = 8 + 4x2x = 24 + 12x-24 = 10x-2.4 = x

Solve for x. 3x + 3 = x + 7 2x + 3 = 7 2x = 4 x = 2 Check it. 6 + 3 = 2 + 7 It checks.

2x + 7 = 1 Therefore, 2x = -6 x = -6/2 x = -3

-1

2x+8 = 6 2x = 6-8 2x = -2 x = -1

x + 2x = 33 3x = 33 3x/3 = 33/3 x = 11

5x+7 = 2x-3 5x-2x = -3-7 3x = -10 x = -10/3

2x + 3 is an expression that is already in simplest form; you cannot "solve" it.

It can be anything. Example: x=1

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How do you solve x plus 3 plus 2x equals x plus 9?