x2 + 4x - 3 = 0
The quadratic formula is x = {-4 ± sqrt[(-4)2 - 4*1*(-3)]}/2
= {-4 ± sqrt[16 + 12]}/2
= {-4 ± sqrt[28]}/2
= {-4 ± 2*sqrt[7]}/2
= -2 ± sqrt[7]
Solve using the quadratic formula
It is: 3x2+6x-11 = 0
That factors to (a + 1)(a + b) a = -1, -b b = -a
X=1
(x-3)(x-2)
(x - 3)(x + 5)
X squared plus b squared equals c squared when x and b squared equals 5 - 2 what does c equal
x = 25 / 3squared + 5
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104
x2 + 6x + 8 = 0 Solve for x.X = -2 or X = -4
Not sure how to put it. The Pythagorean therom states that a squared plus b squared equals c squared. Aren't a, b and c all variables?