By elimination: x = 3 and y = 0
Yes and it works out that x = 3 and y = 4
You can solve lineaar quadratic systems by either the elimination or the substitution methods. You can also solve them using the comparison method. Which method works best depends on which method the person solving them is comfortable with.
You cannot solve one linear equation in two variables. You need two equations that are independent.
Simultaneous equations can be solved using the elimination method.
One way to solve this system of equations is by using matrices. Form an augmented matrix in which the first 2x2 matrix is the coefficient matrix and the 2x1 matrix on its right is the answer. Now apply Gaussian Elimination and back-substitution. Using this method gives x=5 and y=1.
There is no answer because you can't find the value of x and y if you do not have and equals sign.
There are no disadvantages. There are three main ways to solve linear equations which are: substitution, graphing, and elimination. The method that is most appropriate can be found by looking at the equation.
Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution.
There is no simple answer. Sometimes, the nature of one of the equations lends itself to the substitution method but at other times, elimination is better. If they are non-linear equations, and there is an easy substitution then that is the best approach. With linear equations, using the inverse matrix is the fastest method.
No. Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution.
Solve the following systems of simultaneous linear equations using Gauss elimination method and Gauss-Seidel Method 2x1+3x2+7x3 = 12 -----(1) x1-4x2+5x3 = 2 -----(2) 4x1+5x2-12x3= -3 ----(3) Answer: I'm not here to answer your university/college assignment questions. Please refer to the related question below and use the algorithm, which you should have in your notes anyway, to do the work yourself.
Using the elimination method, 3x + (2y) times 18x - 3y - 5 gives the result of 36xy + 3x - 3y - 5.
Elimination is particularly easy when one of the coefficients is one, or the equation can be divided by a number to reduce a coefficient to one. This makes substitution and elimination more trivial.
5x - 4y ≥ -203x - 2y ≤ -8y ≥ -3
The graphical method is a method used to solve algebraical problems by using graphs.
You could multiply the first equation by 3 and the second by -5 and eliminate the x... OR you could multiply the first equation by 7 and the second by 10 and eliminate the y. Either way works.
The matrix is singular because the last equation is the same as the second equation (simply multiplying every term in an equation by the same number (in this case, 2) does not produce an equation with new information). for example 1) 3x=3y 2) 2x=2y has no useful solution beyond the information from 1) that x=y You would get a singular matrix for this. The Gauss-Jordan method will not solve equations which cannot be solved by the old "elimination method".
You can solve the system of equations with three variables using the substitute method, or using matrix operations.
y=5x+2 if y equals -4