First find the mid-point of the line segment which will be the point of intersection of the perpendicular bisector. Then find the slope or gradient of the line segment whose negative reciprocal will be the perpendicular bisector's slope or gradient. Then use y -y1 = m(x -x1) to find the equation of the perpendicular bisector.
Mid-point: (7p+p)/2 and (3q+q)/2 = (4p, 2q)
Slope or gradient: 3q-q/7p-p = 2q/6p = q/3p
Slope of perpendicular bisector: -3p/q
Equation: y -2q = -3p/q(x -4p)
y = -3px/q+12p2/q+2q
Multiply all terms by q to eliminate the fractions:
qy = -3px+12p2+2q2
Which can be expressed in the form of: 3px+qy-12p2-2q2 = 0
2x -5y +19 = 0
Line segment: (3, 5) and (7, 7) Midpoint: (3+7)/2, (5+7)/2 = (5, 6) Slope or gradient: (7-5)/(7-3) = 1/2 Perpendicular slope = -2 Equation: y -6 = -2(x-5) => y = -2x+10+6 => y = -2x+16 So the perpendicular bisector equation is y = -2x+16
An angle comprises to rays meeting at a vertex. An angle bisector is a straight line through the vertex which bisects the angle.
It is a rhombus whose diagonals are perpendicular and meeting each other at right angles.
Minimum and maximum requirements: three straight lines meeting pairwise. Minimum and maximum requirements: three straight lines meeting pairwise. Minimum and maximum requirements: three straight lines meeting pairwise. Minimum and maximum requirements: three straight lines meeting pairwise.
2x -5y +19 = 0
Points: (s, 2s) and (3s, 8s) Slope: 3 Perpendicular slope: -1/3 Midpoint: (2s, 5s) Equation in its general form: x+3y-17 = 0
Line segment: (3, 5) and (7, 7) Midpoint: (3+7)/2, (5+7)/2 = (5, 6) Slope or gradient: (7-5)/(7-3) = 1/2 Perpendicular slope = -2 Equation: y -6 = -2(x-5) => y = -2x+10+6 => y = -2x+16 So the perpendicular bisector equation is y = -2x+16
An angle comprises to rays meeting at a vertex. An angle bisector is a straight line through the vertex which bisects the angle.
Drawing perpendicular bisector for a line:Place the sharp end of a pair of compasses at one end of the line, and open it to just over half of the line. Draw an arc which must intersect the line in the position described. Then put the sharp end at the other of the line and, keeping the compassing at the same length, draw another arc which intersects the first one twice and also the line. Then draw a straight line through the two places where the arcs intersect. This line is the perpendicular bisector. Drawing perpendicular bisector of angle:Places the sharp end of the compass at the point of the angle and, after having opened it arbitraily wide, draw an arc which intersects the two lines meeting to form the angle each once in the said position. Then remove the compass and, always keeping it opened at the SAME length, place the sharp end at each of the two places where the previous arc cuts each of the two lines meeting to form the angle. In this position with the described length, draw a small arc at each of the said places, which should cross each other. Draw a straight line from the point of the angle to this crossing. This should be the bisector of the angle.
It is a rhombus whose diagonals are perpendicular and meeting each other at right angles.
Perpendicular means meeting at a right angle. A right triangle has 2 sides that are perpendicular, so it has 1 pair of sides that are perpendicular They are known as the "legs" of the right triangle.
They both cross paths. Intersecting lines can cross paths in any ways, but perpendicular lines have to cross at 90 degrees.
Perpendicular is straight up and down, having a sharp pitch or slope. It is a style of English Gothic Architecture. So the term would refer to the 'walls' rather than the roof. Parallel in Geometry are straight lines in the same plane, but never meeting. Building may be parallel to each other. Neither word applies
Minimum and maximum requirements: three straight lines meeting pairwise. Minimum and maximum requirements: three straight lines meeting pairwise. Minimum and maximum requirements: three straight lines meeting pairwise. Minimum and maximum requirements: three straight lines meeting pairwise.
If you form the digits with a seven-segment LED display, then all of the digits except '1' have perpendicular lines.
If you mean y = 2x+3 and y = -1/2x+4 then the two lines are perpendicular to each other meeting at right angles.