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Q: How do you work out smallest number divisible by numbers 1 to 12?

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Subtract the smallest number from the largest number.

NO, it is not divisible by all numbers. This is easy to see if you remember that 27 is an odd number and odd numbers are NOT divisible by 2. Then there is the issue that is is NOT divisible by any number greater than itself. That is a lots of numbers that don't work!

The number is divisible by 5 then its end is either 0 or 5 The number is divisible by 9 then the sum of its digits is divisible by 9 If the number is divisible by 5 but not by 10 then it means that the number is divisible by 5 but not by 2, thus it's not an even number. The number is not even so it ends with 5 So the number is written a5a5 or aa55 or 5aa5. a+5+a+5 = 2 x a+10 which must be divisible by 9 if a = 1 then is doesn't work if a = 2 then is doesn't work if a = 3 then is doesn't work if a = 4 then 4545 or 4455 or 5445 are ok if a = 5 then is doesn't work if a = 6 then is doesn't work if a = 7 then is doesn't work if a = 8 then is doesn't work if a = 9 then is doesn't work

The number 2,3,6 and 9 are all divisible by 324...Multiply 2,3,6 and 9; then you get 324 as you answer. To check your work divide all the numbers by 324.

Not sure what you mean with "work"; an even number is a number that is divisible by 2, that is, if you divide it by 2, you get no remainder. An odd number, if divided by 2, has a remainder of 1.

Numbers divisible by 6 will have at least one 2 and one 3 as prime factors because 2 x 3 = 6. The same is true for 2, 4 and 8. Numbers divisible by 4 are also divisible by 2. Numbers divisible by 8 are also divisible by 4 and 2.

if the number is a 2 or more diget number, you add up all of the numbers in the number and when you have the sum, if the sum is divisible by 3 , the whole number is divisible by three EX. 123=6, 6 is divisible by 3 so 123 is divisible by three 447=15 is divisible by 3 so 447 is divisible by 3 989=26 is *NOT* divisible by 3 so 989 is not divisible by three this truly does work for every single number

Best way to work this out: find the highest number below 10,000 that is divisible by 7 (9,996) and divide that by 7 (1,428). 1,428 is the amount of one-, two-, three- and four-digit numbers divisible by 7. Now find the number of one-, two- and three-digit numbers divisible by 7 (which is 994/7 = 142) and subtract this number from 1,428, giving us 1,286.

If it's to be divisible by 5, it must end in 5 or 0. And if it's to be divisible by 3, adding the digits together must result in a multiple of 3.While some numbers that end in zero will still work, you can guarantee that the number won't be divisible by four by choosing a number that ends in five.So you'd need a four-digit number, that ends in 5, whose digits add up to a multiple of 3. The smallest such number would be 1005, and the largest would be 9975.(However, the actual largest number that would fit your question is 9990; remember that I did say some numbers that end in zero would still work.)

You could try dividing by composite numbers but the number that you are testing is divisible by a composite number, then it will be divisible by a prime factor of that composite number and that prime factor will be smaller. It is always easier to work with smaller numbers.

The Range is the distance on the number line that the smallest number is from the biggest number, in sbsolute value. Basically, to find it using math, you would subtract the smallest number in the series of numbers from the largest number in the same series.

That doesn't work. The number has to be divisible by three. Any three consecutive numbers add up to a multiple of three.

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