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First find the midpoint and slope of points (h, k) and (3h, -5k)
Midpoint = (h+3h)/2, (6k+k)/2 = (2h, -2k)
Slope = (-5k-k)/(3h-h) = -6k/2h = -3k/h
Then find the perpendicular slope which is the positive reciprocal of -3k/h which is h/3k
Then substitute these values into the formula of y-y1 = m(x-x1) :-
y-(-2k) = h/3k(x -2h)
y = hx/3k -2h2/3k -2k
Multiply all terms by 3k and the perpendicular bisector equation can be expressed in the form of :-
hx -3ky -2h2 -6k2 = 0
Points: (7, 7) and (3, 5) Midpoint: (5, 6) Slope: 1/2 Perpendicular slope: -2 Use: y-6 = -2(x-5) Perpendicular bisector equation: y = -2x+16 or as 2x+y-16 = 0
The standard form for a straight line equation is y = mx + c, where 'm' is the gradient (slope) and 'c' is the y intercept when 'x' is zero. The equation for the line with details as shown in the question is y = -2x - 4
That is the equation of a straight line intersecting the axis at (4,0) and (0,-4). There is no "answer" as such; an "answer" would imply that you require specific values for x and y at a certain place (e.g where this line meets another line), which clearly cannot be answered with the details given: you have two variables (x and y) and one equation. You MUST have at least the same number of equations as variables in order to solve for x, y etc...
The graph is a straight line, because there's no x2 or y2 in the equation.Now give us a second to massage it around a bit, and then we'll show you howyou can tell the line's details easily. We're not changing anything, just presentingit in a different light:-6x + 2y = -2Add 6x to each side of the equation:2y = 6x - 2Divide each side by 2:y = 3x - 1That's exactly the same equation, but you can look at this form and see immediatelythat the slope of the line is 3, and it cuts the y-axis at the point [ y= -1 ].
The values for the sum 48 are any values if we don't have much given details about these numbers. For instance: 24 + 24 = 48 24 + 2i + 24 - 2i = 48 [Complex numbers] The solution would be more specific if you include either another equation or some extra details that make the problem solvable.
Points: (7, 7) and (3, 5) Midpoint: (5, 6) Slope: 1/2 Perpendicular slope: -2 Use: y-6 = -2(x-5) Perpendicular bisector equation: y = -2x+16 or as 2x+y-16 = 0
Points: (-2, 5) and (-8, -3) Midpoint: (-5, 1) Slope: 4/3 Perpendicular slope: -3/4 Use: y-1 = -3/4(x--5) Bisector equation: y = -3/4x-11/4 or as 3x+4y+11 = 0
First find the midpoint the slope and the perpendicular slope of the points of (p, q) and (7p, 3q) Midpoint = (7p+p)/2 and (3q+q)/2 = (4p, 2q) Slope = (3q-q)/(7p-p) = 2q/6p = q/3p Slope of the perpendicular is the negative reciprocal of q/3p which is -3p/q From the above information form an equation for the perpendicular bisector using the straight line formula of y-y1 = m(x-x1) y-2q = -3p/q(x-4p) y-2q = -3px/q+12p2/q y = -3px/q+12p2/q+2q Multiply all terms by q and the perpendicular bisector equation can then be expressed in the form of:- 3px+qy-12p2-2q2 = 0
The equation is y = 1/8x because there is no y intercept and by doing some homework you'll find it correct
The standard form for a straight line equation is y = mx + c, where 'm' is the gradient (slope) and 'c' is the y intercept when 'x' is zero. The equation for the line with details as shown in the question is y = -2x - 4
See the related link for details.
The details really depend on the equation. It often helps to multiply all parts of the equation by a common denominator, to get rid of the fractions.
Without an equality sign and other information the details given can't be considered to be an equation.
Should be a straight swap. Are you looking for specific details?
Details may vary depending on the equation. Quite often, you have to square both sides of the equation, to get rid of the radical sign. It may be necessary to rearrange the equation before doing this, after doing this, or both. Squaring both sides of the equation may introduce "extraneous" roots (solutions), that is, solutions that are not part of the original equation, so you have to check each solution of the second equation, to see whether it is also a solution of the first equation.
death is inevitable and inescapable. No need for details of proof, because it's obvious and straight out.
That is the equation of a straight line intersecting the axis at (4,0) and (0,-4). There is no "answer" as such; an "answer" would imply that you require specific values for x and y at a certain place (e.g where this line meets another line), which clearly cannot be answered with the details given: you have two variables (x and y) and one equation. You MUST have at least the same number of equations as variables in order to solve for x, y etc...