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Q: How do you work out this problem 93 (68 7)?
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What is b in the problem 68 equals 7 b - 9?

68 = 7b - 9 -7b = -68-9 b = (-68-9)/-7 = 11


What is x to the problem 68 plus 28x-28 equals 236?

68 + 28x - 28 = 236 28x + 68 - 68 -28 + 28 = 236 - 68 + 28 28x = 196 x = 7


What is the product of the first 5 prime numbers.The average of 5 numbers is 55 if 68 and 93 are added to them what will be the resulting average?

The first 5 primes are 2, 3, 5, 7, 11 Their product = 2310. Average of 5 numbers is 55 so their sum is 55*5 = 275. Two numbers, 68 and 93 are added so the new sum of seven numbers is 275 + 68 + 93 = 436 So the new average is 436/7 = 62.3 (to 1 dp).


What divided by 7 equals 68?

476/7 = 68


What is 7 divided by 93?

0.0753