Follow this procedure:
1). Ask a question. (You haven't done that yet.)
2). Consider the equation as it relates to the question.
3). Operate on the equation, always using legitimate algebraic manipulations,
so as to rearrange the equation, or isolate the variables, as required to answer
the specific question that has been asked.
That's the best way to "work it out".
It depends on the rest of the equation and the form it takes.
x equals y
Transitive property: If 8 equals x and x equals y, then 8 equals y.
y = 3, x = 1 y = 4, x = 2 Anything where y is two greater than x will work.
If [ y = x + 2 ], then x is not -1 when y = 5.If [ y = x + 2 ],then when x = -1, y = 1,and when y = 5, x = 3.
x equals -12 and y equals 1/4 of -12, so y = -3.
There is no one solution to this problem. For example: y = x2 y = 5x y = x + 20 y = 2x / 5 + 23 These are just four of the infinite set functions that would give "y" a value of 25 when x = 5.
its so easy work it out your self
x=y
The result of the equation x + 2y - 2x - y equals x simplifies to y - x.
2x = y + 7 x - 2 = y substitute the y from the second equation into the first: 2x = x - 2 + 7 2x = x+5 x = 5 --> y = 5 - 2 y = 3
26.
x=4 y=4