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Q: How do you factor 3x squared minus 49?

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It is a difference of squares. 9x^2-49=(3x+7)(3x-7)

(8w + 7)(8w - 7)

If that's +42x + 49, the answer is (3x + 7)(3x + 7) or (3x + 7)2 If that's -42x + 49, the answer is (3x - 7)(3x - 7) or (3x - 7)2

7 squared and 11 squared have no common factor greater than 1.

They are 100 minus 49 = 51

49 - x2 = -(x2 -49) = - (x-7)(x+7) divide by x -7 Answer: -(x+7) = -x-7

(x-7)(x+7) but what if the question was x squared PLUS 49 x^2 + 49 help

There's a formula for the "difference of squares." If your question was x2 - 49, the answer would be (x + 7)(x - 7). In your case, substitute the square root of 47 for the 7 in my example.

This is called an inequality. If x squared is greater than or equal to 49, then x is plus or minus 7 or greater than plus 7 or less than - 7.

150x2 - 294 = 6*(25x2 - 49) The expression in the brackets is a difference of two squares, so: 6*(5x - 7)*(5x + 7)

25a2-70a+49 = (5x-7)(5x-7) when factored

b2+14b+49 = (b+7)(b+7) when factored

It is: (x-7)(x+7) when factored

7 x 7 = 49

7 x 7 = 49

Yes because if x2-14x+49 then it is (x-7)(x-7) when factored

25 squared plus 49 squared is equal to 3,026.

(x - 7)(x2 + 7x + 49)

7 squared = 49

27v2 - 147 = 3*(9v2 - 49) = 3*(3v - 7)*(3v + 7)

63

7 squared is 49 and 5 squared is 25. So the difference is 49-25=24

42

101 minus 49 is 52.

49