To find the HCF of 3 numbers you first need to write them as the product of their prime factors. In this case you get: 11 = 11 33 = 3x11 121 = 11x11 The next step is to identify any common prime factors. In this case, all three numbers have an 11 as a prime factor. Therefore, the HCF of 11, 33 and 121 is 11.
As a product of its prime factors: 3*7 = 21
2x2x3x5
Yes, 62 and 121 are relatively prime
11 multiply by 11 equals 121 so the product of 121 equals 11
11 x 11 = 121
There are no two prime numbers that equal 121. 121 is not a prime number itself, but is a product of 11*11.
As a product if its prime factors: 11 times 11 = 121
Factors of 121 are 1, 11, and 121 Prime factorization of 121 is 112 (11 x 11)
write the number 14as a product of prime factor?
To find the HCF of 3 numbers you first need to write them as the product of their prime factors. In this case you get: 11 = 11 33 = 3x11 121 = 11x11 The next step is to identify any common prime factors. In this case, all three numbers have an 11 as a prime factor. Therefore, the HCF of 11, 33 and 121 is 11.
write the prime factorization of the number. simple as that.
A number as a product of prime numbers would be "x".
The prime factor of 7 is 7. The prime factor of 121 is 11.
As a product of its prime factors: 2*5*17 = 170
As a product of its prime factors: 3*7 = 21
2x2x2x2x3