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Q: How do you get the number 13 using only numbers 1 and 5 and 7 and 8 using the numbers only once?

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998,000

3! = 6.

17 = (4+2)*3 - 1

it cant

only using the numbers once

6*5*4*3=360

2,5,13,647,809

567 - 349 = 218 or 567 - 218 = 349

There are 3,628,800 different permutations that can be made when using the numbers 0 through 9, if each number is only used once in each combination.

18

-8

There is only one combination. In a combination the order of the numbers does not matter so the only combination is 0123456789. This is the same as 1326458097

I may be wrong but it seems impossible. There probably is proof somewhere if it is.

4*6+1

4x4x3+2

The Cars For Kings Company is putting out the new models. They want to put a 4-digit number on the back of each new model car. They have decided to use only the numerals 2,5,7,8. Each numeral can only be used once in a number. How many different numbers can the Cars For Kings Company put on the backs of the new model cars?

The smallest value Roman numeral using each symbol only once would be MCDXLIV = 1444

24 of them.

Imposible.

(5+7)*(5-3)=12*2=24

Six: 234, 243, 324, 342, 423, and 432.

3

1

36 - 18

There is no such set of numbers.

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