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How do you write 1.6 Cr in number?
1600000
How do you write out 31.6 million?
1 million = 10 lakhs (in Indian rupees) Then, 31.6 millions = 3 cr 16 lakhs
Write the number that is 100 less?
write the number that is 100 less
How do you write 75 percent of a number?
You write a number, not wright! It would be written as 75% of [the number].
How do you write 7 as an ordinal number?
To write 7 as an ordinal number, you would write it as "seventh."
How do you write 1.6 Cr in number?
1600000
Which sports federation in India is to receive assistance of rs25 crores from the bcci?
football
Which answer is the oxidation number for Cr in Cr2Omc019-1jpg?
The oxidation number for Cr in Cr2O7^2- is +6.
What is the change in the oxidation number of Cr?
The change in oxidation number of Cr depends on the specific reaction or compound involved. For example, in the reaction from Cr(III) to Cr(VI), the oxidation number of Cr changes from +3 to +6, indicating an increase in oxidation state.
What is the atomis number of Cr?
The atomic number of Cr, which stands for chromium, is 24.
What is the oxidation number of Cr2O3?
+3 for Cr and -2 for O
What is the oxidation number of Cr in CaCrO4?
+2 for Ca, +6 for Cr, -2 for each O
Suppose you have 20.8 g of Cr What number of moles of Cr is present?
.400 moles
Why do you write Dr for debit and Cr for credit in accounts?
From another web site: Dr = Debit Record Cr = Credit Record
What is the oxidation number of Cr in CrBr?
The oxidation number of Cr in CrBr is +3. Since Br has an oxidation number of -1 and there is only one Br atom in the compound, the oxidation number of Cr must be +3 to balance the charges to zero.
Which element is a transition element with a mass of 52?
Chromium (Cr) is a transition element with a mass of 52. Its atomic number is 24.
What is the oxidation number for Cr in MgCrO4?
The oxidation number of Cr in MgCrO4 is +6. This is because oxygen is typically assigned an oxidation number of -2, and the overall charge of the compound is 0, so the oxidation number of magnesium (+2) and oxygen (-2) must be balanced by the oxidation number of Cr (+6).
