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How does one factor two D minus two times four D minus eight equals zero?
Wiki User
∙ 16y ago
I think your equation is this: (2d - 2)(4d - 8) = 0 If that is correct, then you have a quadratic equation, but IT'S ALMOST COMPLETELY FACTORED ALREADY! You could factor out a two from the first term in parentheses, and you could factor out four from the second parenthetical term. That give you: 2(d-1)4(d-2) = 8(d-1)(d-2) = 0 I think that's as far as you need to go to answer the question. But . . . You can divide both sides of the equation, now, by 8, which gives you: (d-1)(d-2) = 0 You therefore have two roots, one at d = 1 and the other at d = 2.
Wiki User
∙ 16y ago
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