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secx = 1/cosx

and 1/cotx = tanx, therefore

1/cosx + tanx = 1 + sinx/cosx, and

sin/cos = tanx, therefore

1/cosx + tanx = 1 + tanx, therefore

1/cosx = 1, therfore

1 = cosx.

So, therfore, it is not neccesarily true.

But if you mean

secx plus 1 divided by cotx equals (1 plus sinx) divided by cosx(this is probably what you mean) Let's start over!

secx = 1/cosx

and 1/cotx = tanx, therefore

1/cosx + tanx = (1+sinx)/cosx therefore

1/cosx + tanx = 1/cosx + sinx/cosx

sinx/cosx = tanx therfore

1/cosx + tanx = 1/cosx + tanx

Do you think this is correct? Subtract both sides by 1/cosx + tanx:

0 = 0

So, therefore, this is correct!

(BTW, I'm in Grade 6! :P)

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โˆ™ 2011-07-06 20:12:28
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Algebra

21 cards

During the 1930s the new deal legislation was proposed by president Franklin Roosevelt to bring the US out of the great depression

What economic function does the government attempt to correct for in market failures like monopolies

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Algebra

21 cards

During the 1930s the new deal legislation was proposed by president Franklin Roosevelt to bring the US out of the great depression

What economic function does the government attempt to correct for in market failures like monopolies

Protection from foreign enemies is established in the Constitutional promise to provide for what

The sharing of ideas and experimental findings with others

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Q: How does secx plus 1 divided by cotx equal 1 plus sinx divided by cosx?
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