No
A number that has only one and itself as factors is a prime number and so therefore it can't have four other identical factors.
23 is a prime and so its only factors are 1 and 23. The product will be smaller than 23 but it is not possible to be certain how the product will compare with 1.
Assuming the coefficients are real, the discriminant is non-negative. The reason for this is that in this case, if the solutions are complex, they must needs be conjugats of one another, i.e., two different solutions.
Please restate your problem. When dealing with factors you usually have to compare two or more numbers.
lol
Because they separated into separate beings early in the cell division process. After that, a quadrillion factors are involved in the minuscule differences all along the development process. This is how they become different people.
16 is a number that has four identical even factors.
Five identical prime factors : 32, 96. Four identical prime factors : 16, 48, 80, as well as 81. Three identical prime factors : 8, 24, 40, 56, 72, 88, as well as 27, 54. Two identical prime factors : All multiples of 4 not yet listed (4, 12, 20...), all multiples of 9 not yet listed (9, 18, 36...), as well as 25, 50, 75, 100, and 49 and 98. Your teacher forgot "six identical prime factors" : 64.
2 x 3 x 11 = 66
in sentences
Constants are the factors which do not change. Variables are the factors which change. If that is what you are referring to.
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A number that has only one and itself as factors is a prime number and so therefore it can't have four other identical factors.
10 and 10
Homozygous
A square number.
45 does not have 3 identical factors: unless you mean 1*1*1.