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Let the distance be d km

time = speed/distance

The journey to the second town took: t1 = d km ÷ 2.5 km/h = d/2.5 hr = 2d/5 hr

The journey back to the first town took: t2 = d km ÷ 3 km/h = d/3 hr

The total time is: t1 + t2 = 7 hr 20 min = 7 + 20/60 hr = 7⅓ hr

→ 2d/5 + d/3 = 7⅓

→ (6d + 5d)/(3×5) = 7⅓

→ 11d = 7⅓ × 15

→ d = ((7×3+1)/3 × 15)/11

→ d = (22/3 × 15)/11

→ d = 22/11 × 15/3

→ d = 2 × 5 = 10

The towns are 10 km apart.

Checking:

t1 = 10 km ÷ 2.5 km/h = 4 hr

t2 = 10 km ÷ 3 km.h = 3⅓ hr

t = t1 + t2 = 4 hr + 3⅓ hr = 7⅓ hr

1 hr = 60 min

→ ⅓ hr = ⅓ × 60 min = 20 min

→ t = 7 hr 20 min.

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Q: How far apart are two towns if you walk from one town to another at an average speed of 2.5 kmh and return at an average speed of 3 kmh and the time taken for the double journey was 7 hr 20 min?
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