Q: How is 7 5 out of 8 written as an improper?

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It is 47/8.

1 5/8 = (1x8+5)/8 = 13/8 (as an improper fraction).

31/83 7/8:= [(8 * 3)+7]/8= [24 + 7]/8= 31/8 in improper fraction

9 5/8 - 1 7/8 = 7 3/4 ------------------------------- It is often easier to convert mixed numbers to improper fractions, do the sum and convert any resulting improper fraction back to a mixed number: 9 5/8 - 1 7/8 = (9×8+5)/8 - (1×8+7)/8 = 77/8 - 15/8 = 62/8 = 31/4 = (7×4+3)/4 = 7¾

5 1/8 + 14/8 = 6 7/8 This is a mixed number and improper fraction. The least confusing way is to convert the first to another improper fraction, where 5 1/8 = (41/8) Now the addition is 41/8 + 14/8 = 55/8 = 6 7/8

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6 7/8 as can be written as improper fraction as 55/8.

It is 47/8.

It is 39/8.

5/8 cannot be written as an improper fraction.

4 5/8 = (4x8+5)/8 = 37/8

improper form is when a mixed number (i.e. 1 2/3, 4 5/8, etc.) is written as a normal fraction (i.e. 1 2/3 improper is 5/3, 4 5/8 improper is 37/8, etc.)

1 5/8 = (1x8+5)/8 = 13/8 (as an improper fraction).

31/83 7/8:= [(8 * 3)+7]/8= [24 + 7]/8= 31/8 in improper fraction

9 5/8 - 1 7/8 = 7 3/4 ------------------------------- It is often easier to convert mixed numbers to improper fractions, do the sum and convert any resulting improper fraction back to a mixed number: 9 5/8 - 1 7/8 = (9×8+5)/8 - (1×8+7)/8 = 77/8 - 15/8 = 62/8 = 31/4 = (7×4+3)/4 = 7¾

5 1/8 + 14/8 = 6 7/8 This is a mixed number and improper fraction. The least confusing way is to convert the first to another improper fraction, where 5 1/8 = (41/8) Now the addition is 41/8 + 14/8 = 55/8 = 6 7/8

Multiply by the second fraction's reciprocal. 7/4 divided by 8/5 = 7/4 x 5/8

3 5/8:= [(8*3)+5]/8= [24+5]/8= 29/8 in improper fraction