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Initial upward speed = 7.61 m/s

Final upward speed (at the point of maximum height) = 0

Time to reach maximum height = (7.61) / (9.8) = 0.77653 second

Average speed during that time = 1/2 ( 7.61 + 0) = 3.805 m/s

Height = 3.805 x 0.77653 = 2.9547 meters (rounded) = about 9.7 feet

Doesn't seem like much of a height for a strong toss; but the math looks OK.

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βˆ™ 2009-09-04 19:55:39
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Q: How is it that A ball is projected straight up from the ground with a speed of 7.61 meters per second To what maximum height will the ball go when gravity equals 9.80 meters per second squared?
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