The angle of elevation is increased as the plane flies closer because of the decreasing distance.
The angle of elevation is looking at an object above your line of sight.
It is the alternate angle to the angle of elevation
If the base of the elevation is at a distance d from the observer, then the highest point is at a height = d*tan(angle of elevation)
The front elevation is in the centre in both projections. In 1st angle projection the end elevation is on the opposite side of the front elevation and the plan view is below the front elevation. In 3rd angle projection the plan view is above the front elevation and the end elevations are on the same side as viewed
It can be shown that:height = (d tan α tan β)/(tan α - tan β)where: α is the angle closest to the objectβ is the angle further away from the objectd is the distance from the point of angle α to the point of angle βThus: height = (80 ft × tan 45° × tan 34°)/(tan 45° - tan 34°) ≈ 165.78 ft
distance and angle of elevation are closely related as the more closer you move, the half is the angle of elevation. for e.g. if you travel 30m and cover 15m then, the angle of elevation will be half of what you started with. this can be also proved by a live example as when you have the angle of elevation as 90 degree, then the distance can be zero....
Angle of elevation is looking upwards to an object and angle of depression is looking downwards to an object
The angle of elevation is looking at an object above your line of sight.
It is the alternate angle to the angle of elevation
If the base of the elevation is at a distance d from the observer, then the highest point is at a height = d*tan(angle of elevation)
The height of the tree if the angle of elevation is 40 N, would be 60 m.
Angle of elevation: tangent angle = opposite/adjacent and by rearranging the given formula will help to solve the problem
A sextant.
The front elevation is in the centre in both projections. In 1st angle projection the end elevation is on the opposite side of the front elevation and the plan view is below the front elevation. In 3rd angle projection the plan view is above the front elevation and the end elevations are on the same side as viewed
i dont care about math even though i use it.
It can be shown that:height = (d tan α tan β)/(tan α - tan β)where: α is the angle closest to the objectβ is the angle further away from the objectd is the distance from the point of angle α to the point of angle βThus: height = (80 ft × tan 45° × tan 34°)/(tan 45° - tan 34°) ≈ 165.78 ft
yes