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Check the sum of the digits, if the sum divisible by 3 then the number is divisible by 3. Example 910: the sum of digits= 9 + 1 + 0 = 10, but 10 is not divisible by 3, so the number 910 is not divisible by 3. Example 2154: the sum of digits = 2 + 1 + 5 + 4 = 12, this sum is divisible by 3, so the number 2154 is divisible by 3. if the sum is long you can check the sum of the sum and apply the same rule. Example 52498731: the sum of digits = 5 + 2 + 4 + 9 + 8 + 7 + 3 + 1 = 39, the sum of the digits for 39 = 3 + 9 = 12, so the original number, i.e. 52498731 is divisible by 3.

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Q: Determine if a number is divisible by 3?

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To determine if a number is divisible by 6, it must be divisible by both 2 and 3. To determine if a number is divisible by 2, it should be even - in other words, it should end with 0, 2, 4, 6, or 8. To determine if a number is divisible by 3, the sum of its digits should be divisible by 3. 54,132 is an even number, so it is divisible by 2. 5 + 4 + 1 + 3 + 2 = 15, which is divisible by 3, so 54,132 is divisible by 3. Since 54,132 is divisible by both 2 and 3, it is divisible by 6.

To determine if a number is divisible by 3, add all the digits. If the sum is divisible by 3, so is the number. 8+4+3+5 = 20, which is not divisible by 3 (not a multiple of 3). So, 8435 is not divisible by 3.

If the sum of the digits of a given number is divisible by three, the number is divisible by three.

Yes. An easy way to determine if a number is divisible by 3: Sum the digits of the number: 7+9+0+2 = 18. If that sum is divisible by 3 then the number is also. As you can see the sum is 18, so 7902 is divisible by 3. 7902/3 = 2634

Yes, it is. Your answer is 406. You can determine whether a number is divisible by 3 by adding the digits. If the sum of the digits (in the above, 1+2+1+8 = 12) equals 3, the number is divisible by 3.

you add the numbers together and if that is divisible by three then so is that number for example: the number 111, you would do 1+1+1=3 so 111 is dividable by 3; or the number 1,620, 1+6+2+0= 9 (which is divisible by 3) so 1,620 is divisible by 3

That the number is divisible by 4* and the sum of its digits is a multiple of 3. *If the number has three of more digits then it is only necessary to look at the tens and units to determine if it is divisible by 4, as 4 is a factor of 100 and therefore of any multiple of 100. Examples : 75 : is not divisible by 4 although its digits total 12 which is a multiple of 3. 132 : is divisible by 4 as 32 is divisible by 4, and its digits total 6 which is divisible by 3, then 132 is divisible by 12.

Converse:If a number is divisible by 3, then every number of a digit is divisible by three. Inverse: If every digit of a number is not divisible by 3 then the number is not divisible by 3? Contrapositive:If a number is not divisible by 3, then every number of a digit is not divisible by three.

A number is divisible by 12 if it is divisible by 3 AND it is divisible by 4. Rule 1a (Divisibility by 3): Add up all the digits of the number. Is this number divisible by 3? Rule 1b (Divisibility by 4): Is the number formed by the last two digits of the original number (the number left after deleting the hundreds, thousands, millions etc) divisible by 4? If the answer to 1a is NO, then the number is not divisible by 3 and so not divisible by 12. In this case, obviously, rule 1b is irrelevant. If the answer to 1b is NO, then the number is not divisible by 4 and so not divisible by 12. If the answer to both 1a and 1b is YES, then the number is divisible by 12.

yeah3 9 15 21 27 and so on(every other multiple of three)But if you have a large number, like 755253, and don't have a calculator handy, then use sum of digits to determine if divisible by 3.Then if the number is divisible by 3 and divisible by 2, then it is also divisible by 6.So in this case: 7 + 5 + 5 + 2 + 5 + 3 = 27, which is divisible by 3, but the original number is odd, so the number is not divisible by 6.

If the sum of the digits of a number is divisible by 3, then the number is divisible by 3.

There is no such number. Since 6 is divisible by 3, then any number that is divisible by 6 automatically has to be divisible by 3.

How about: 120

How about: 960

35 is not divisible by 3.

If the sum of the digits of a number is divisible by 3 ,then the number is divisible by 3.. is 36 is right

If a number is not divisible by 3 then it is not divisible by 9.

Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.

If this is a T-F question, the answer is false. It is true that if a number is divisible by 6, it also divisible by 3. This is true because 6 is divisible by 3. However, the converse -- If a number is divisible by 3, it is divisible by 6, is false. A counterexample is 15. 15 is divisible by 3, but not by 6. It becomes clearer if you split the question into its two parts. A number is divisible by 6 if it is divisible by 3? False. It must also be divisible by 2. A number is divisible by 6 only if it is divisible by 3? True.

the number 3 is divisible by 3

Yes, every number that's divisible by 9 is divisible by 3

The number 1,260 is divisible by 2, 3, 4, 5, 6, 9, and 10.

If a number is even (divisible by 2) and divisible by 3, then it must also be divisible by 6.

Since 3 is a factor of 6, any number divisible by 6 is also divisible by 3. But since 2 is also a factor of 6, then any number divisible by 6 must also be divisible by 2. This means that any number divisible by 6 is an even number. So if a number is odd and it is divisible by 3, then it is not divisible by 6. For example, 12 is divisible by 3, but since it is even, it is also divisible by 6. But 15 is divisible by 3, and it is odd, so it is not divisible by 6.

If a number is divisible by 3 or more numbers than that number is composite, if not than it is prime.