43.26661530556787
sqrt(24*36) = 29.4sqrt(24*36) = 29.4sqrt(24*36) = 29.4sqrt(24*36) = 29.4
sqrt (2 x 36 x 36) ie 50.94 inches
A rectangle with a perimeter of 36 units can have sides of any length as long as the lengths of the two differently-sized sides are equal to 18. For example, a rectangle with sides of 10 units and 8 units (don't forget to state what these units are, whether they are inches or centimetres or any other similar measurement), would have a perimeter of 36.
It could be the measurements of a woman, bust 36 inches, waist 24 inches, hips 36 inches.
The rectangle has a length of 12 cm and a width of 3 cm.
Use Pythagoras' therorem to find the diagonal of the rectangle which is 12 times the sq rt of 13
The diagonal is 45.61 feet.
36 inches
(Diagonal)2 = (36)2 + (26)2 = 1,972Diagonal = sqrt(1,972) = 44.4072 (rounded)
Perimeter = 25+36+25+36 = 122 units of measurement Use Pythagoras' theorem to find the other side of the rectangle
Using Pythagoras: 322+362 = 2320 and the square root of this is the length of the diagonal
a2 + b2 = c2. 62 + 82=c2. 36+64=c2. 100=c2. sqrt(100)=sqrt(c2). c=10. So the diagonal is 10 m. long.
By Pythagoras, (Diagonal)2 = 362 + 562 = 1296 + 3136 = 4432 sq ft So diagonal = +sqrt(4432) = 66.75 ft
The dimensions are 27cm by 36 cm, solved with the help of Pythagoras' theorem
Using Pythagoras its base works out as 36 and so 36*15 = 540 square units
60 feet Solved with the help of Pythagoras' theorem
864