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How long is the diagonal of a rectangle with the length of 30 yd and the width of 30 yd?
Wiki User
∙ 9y ago
The diagonal of a rectangle with the length of 30 yd and the width of 30 yd is approximately 42.43 yd
Wiki User
∙ 9y ago
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How do you find the width and length of a rectangle if you only know the diagnol?
If the only known fact is the length of the diagonal then the width and length of the rectangle CANNOT be determined. The diagonal could be that of a square, or of a rectangle that is very long but quite narrow. Consequently at least one more fact is required such as; the dimension of either the length or the width, or the angle that the diagonal makes to the base of the rectangle or even the area of the rectangle.
Find the width of a rectangle with a length of 8cm and a diagonal 10cm long?
infinitely far
What are the dimensions of a diagonal of a rectangle of 42in?
Anything you want, so long as (Length in inches)2 + (Width in inches)2 = 1,764
A rectangle is 12 cm long and 9 cm wide Its diagonal is labeled 2x - 11 What is the value of x?
According to the given length & width, the diagonal must be 15 cm.So,2X - 11 = 152X = 26X = 13
What is the width of a rectangle compared to the length?
The width and the length are independent. You can have a very long rectangle which is very wide or not wide at all. They are related when it comes to calculating area or perimeter of the rectangle. Perhaps that is what you meant?
How do you find the width and length of a rectangle if you only know the diagnol?
If the only known fact is the length of the diagonal then the width and length of the rectangle CANNOT be determined. The diagonal could be that of a square, or of a rectangle that is very long but quite narrow. Consequently at least one more fact is required such as; the dimension of either the length or the width, or the angle that the diagonal makes to the base of the rectangle or even the area of the rectangle.
Find the width of a rectangle with a length of 8cm and a diagonal 10cm long?
infinitely far
How long is the diagonal of a rectangle with the length of 12cm and width of 9cm?
15 cm Solved through Pythagoras' theorem.
What are the dimensions of a diagonal of a rectangle of 42in?
Anything you want, so long as (Length in inches)2 + (Width in inches)2 = 1,764
What is the formula for a rectangle 23'0 long x 9'6 wide what is the diagonal length?
-- A rectangle has no 'formula'. -- The length of the diagonal is 24feet 10.62inches (rounded)
What is the sum of the length of the diagonals of a 12 by 16 rectangle?
If the length of a rectangle is 12 and the width of the rectangle is 16, by the Pythagorean theorem we know that one diagonal is 20 units long. You can draw two diagonals within a rectangle, so the length of both diagonals together is 20+20 = 40 units.
What is the length of the diagonal of a rectangle 9 centimeters wide and 12 centimeters long?
15 cm for the diagonal.
Where is the length and width of a rectangle located?
A rectangle is a four-sided figure with two long sides and two short sides. The two long sides are the length of the rectangle. The two short sides are the width of the rectangle.
What is the perimeter of a rectangle that is 1.6 meters long and 0.8 meters wide?
Perimeter of rectangle = 2 x (length + width) = 2 x (1.6 + 0.8) = 2 x 2.4 = 4.8 meters
A rectangle is 12 cm long and 9 cm wide Its diagonal is labeled 2x - 11 What is the value of x?
According to the given length & width, the diagonal must be 15 cm.So,2X - 11 = 152X = 26X = 13
What is the area of a rectangle 5cm long by 1cm wide?
Area of a rectangle= Length * width Length= 5cm Width= 1cm Area=5cm *1cm =5cm2
The length of the rectangle below is 26.63 inches. If the diagonal makes an angle of 42.6 and ordm with this side find the measure of the width of the rectangle rounded to the nearest tenth of an inch?
The diagonal creates a right angled triangle with one pair of long and short sides - the diagonal is the hypotenuse. We know the angle between the long side (adjacent) and hypotenuse as 42.6°; We want to find the length of the short (width) side (opposite). We can use the Tan ratio: tan = opposite/adjacent → opposite = adjacent × tan → width = 26.63 in × tan 42.6° = 24.487... in → width is 24.5 inches to the nearest tenth of an inch.
