2ⁿ = 20000 → log(2ⁿ) = log(20000) → n log(2) = log(20000) → n = log(20000)/log(2) You can use logs to any base you like as long as you use the same base for each log → n ≈ 14.29
As long as it can displace a volume of water equal to its mass (ie its density is less than that of the water) it will float. Most paper will have a density less than that of water (or can be so folded) so will float.
There are a large number of different places you can go to in order purchases log houses. A particularly good one is Screwfix as you can get log houses at very good prices as long as you are willing to assemble it yourself.
5x-2 = 70 ⇒ (x-2) log 5 = log 70 ⇒ x = log 70/log 5 + 2 ≈ 4.640 (You can use any base you like for the logs, as long as you use the same base for both of them.)
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Actually, the steel needle can float on water as well, so long as the surface tension is not broken. Answering the question, the buoyancy (ratio of density to that of displaced water) causes the log to float.
An object will float on water if it has less density than the water. Or than any other liquid on which it is supposed to float.
It is lighter than water.
A log? As in a log that came from a tree, right? If the density of water was decreased enough, such that it is now lower than a log's density, then the log would no longer float, but sink.
long float myfun();
it will float as long as it is not fully covered water.
you hav to log out nd log in nd then it will be there how long it takes yhu to log out nd log in iz how long it takes
no it doesn't long to log in
it can float as long as i feakin say so jo cod
i wann't ask the range of double float and long double float??
log, do you mean long?
The water extracted by the wood log while floating is of equal weight of the wood or more. For this reason, the log of wood floats while a steel needle sinks.