Is that 144 square feet, as in 12' x 12'?
If that is the case, you would need a minimum of 81 bricks. If the patio is indeed square, or 12' by 12', each side is 144", or 9 16" bricks. 9 x 9 = 81 bricks.
If the patio is not square, you may need extra bricks on one or both sides if the width is not evenly divisible by 16 inches.
About 240 three inch by eight inch bricks would be need for create a ten foot by four foot patio. It would be preferable to purchase another 24 or 10 percent more for wastage.
you would need 12...
81 bricks.12 feet times 12 inches per foot = 144 inches.144 inches divided by 16 inches per brick = 9 bricks in length/width.9 bricks (length) times 9 bricks (width) = 81 bricks.
A 12 x 12 inch brick is 1 square foot. A 20 x 20 (foot) patio is 400 square feet, so you would need 400 bricks.. this assumes you are butting the bricks fairly tight, not leaving large seperations between them, etc...
In a perfect world, 225 will do it. In real life, better buy about 300
needs more information to be accurately answered.
6 inches is half a foot so it takes four 6 by 6 inch bricks to make one square foot. 348 x 4 = 1392. So you'll need 1392 bricks.
225 bricks. 16in * 16in = 256 sq. in. 20ft = 240in. 240in * 240 in = 57,600 sq. in. 57,600 sq. in. / 256 sq. in. = 225. 225 bricks is your answer.
Gee, a square foot is 12x12, difficult problem.
A 12" x 12" brick covers an area of one square foot. Assuming your patio is 396 square feet, then you would need 396 bricks. However, you will almost certainly have to cut some bricks to fit them into whatever shape your approximately 20' x 20' patio will be, so you should figure on needing a few more. The rule of thumb is to order what you need plus 10% extra, but make sure you can return the unused bricks. Area covered by 12x12 inch brick is 144 square inches. That is 1 square foot. Total area of the patio is 396 square foot. Number of bricks required = 396/1 = 396 bricks. Source: www.icoachmath.com That gives you the extra ten percent you'll need to compensate for cutting, breakage, etc.