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9x8x7

because the first digit has 9 possibilities (1-9), the second digit has 8 possibilities (1-9 minus the one already used), and the 3rd has 7 possibilities (1-9 minus the 2 already used)

So there are 504 numbers like that

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12y ago
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Q: How many 3-digit numbers can be formed by using the digits 1 to 9 if no digit is repeated?
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