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10; 888, 798, 789, 978, 879, 996, 969, 699

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Q: How many 3 digit numbers are there in which the sum is 24?
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What are all the two digit numbers that are divisible by both the sum and the product of its digits?

There are three such numbers: 12, 24 and 36.


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-- If you accept 4-digit numbers with 'zero' as the first digit, thenthere are 24 possibilities, and their sum is 119,988 .-- If the first digit can't be a 'zero', then there are 18 possibilities,and their sum is 115,992 .Note: I didn't repeat any digits.-- If you allow repeated digits, and accept leading zeros, then there are 256 possibilities,and their sum is 1,279,872.-- If you allow repeated digits but not leading zeros, then there are only 192 possibilities,and their sum is 1,247,904.


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