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Q: How many 4 digit combinations can be made from the numbers 0 to 9?

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Number of 7 digit combinations out of the 10 one-digit numbers = 120.

There are 38760 combinations.

120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.

The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.

10 Combinations (if order doesn't matter). 3,628,800 Possiblilities (if order matters).

66

15

6 ways: 931,913,139,193,391,319

10,000

2304

There are 1140 five digit combinations between numbers 1 and 20.

There are 840 4-digit combinations without repeating any digit in the combinations.

7

There are 9 1-digit numbers and 16-2 digit numbers. So a 5 digit combination is obtained as:Five 1-digit numbers and no 2-digit numbers: 126 combinationsThree 1-digit numbers and one 2-digit number: 1344 combinationsOne 1-digit numbers and two 2-digit numbers: 1080 combinationsThat makes a total of 2550 combinations. This scheme does not differentiate between {13, 24, 5} and {1, 2, 3, 4, 5}. Adjusting for that would complicate the calculation considerably and reduce the number of combinations.

9^9 = 387420489 different digit combinations.

The answer is 10C4 = 10!/[4!*6!] = 210

If the numbers are not allowed to repeat themselves then 362,880. * * * * * That is the number of permutations, not combinations. In a combination the order of the digits does not matter. So there is only one 9-digit combination.

You would get 4!/2! = 12 combinations.

If there are no restrictions on duplicated numbers or other patterns of numbers then there are 10 ways of selecting the first digit and also 10 ways of selecting the second digit. The number of combinations is therefore 10 x 10 = 100.

There are 1,120,529,256 combinations.

56 combinations. :)

If each can be used again, it is 7x7x7x7 or 2401 combinations. If not it is 7x6x5x4 or 840 combinations

Only three: 12, 13 and 23. Remember that the combinations 12 and 21 are the same.

There are 9C3 = 84 combinations.

How many numbers are there between 0000 and 9999?