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If every number can be used as many times as you like, there are 104 = 10000 different combinations. If each number can only be used once, there are 9!/(9 - 4)! = 5040 combinations.

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โˆ™ 2009-08-15 05:17:25
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Q: How many 4 digit combinations can be made from the numbers 0 to 9?
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Related questions

If using 7 single digit numbers how many different combinations can you get?

Number of 7 digit combinations out of the 10 one-digit numbers = 120.


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How many 5 digit combos in 30 numbers?

The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.


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10 Combinations (if order doesn't matter). 3,628,800 Possiblilities (if order matters).


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If using numbers 1 through 8 how many different 4 digit combinations can be made?

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If using numbers 1 through 4 how many different 4 digit combinations can be made?

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If using numbers 0 through 9 how many different 4 digit combinations can be made and what are they?

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There are 1140 five digit combinations between numbers 1 and 20.


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There are 9 1-digit numbers and 16-2 digit numbers. So a 5 digit combination is obtained as:Five 1-digit numbers and no 2-digit numbers: 126 combinationsThree 1-digit numbers and one 2-digit number: 1344 combinationsOne 1-digit numbers and two 2-digit numbers: 1080 combinationsThat makes a total of 2550 combinations. This scheme does not differentiate between {13, 24, 5} and {1, 2, 3, 4, 5}. Adjusting for that would complicate the calculation considerably and reduce the number of combinations.


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If using numbers 0 through 9 how many different 2 digit combinations can be made?

If there are no restrictions on duplicated numbers or other patterns of numbers then there are 10 ways of selecting the first digit and also 10 ways of selecting the second digit. The number of combinations is therefore 10 x 10 = 100.


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How many different combinations are possible multiplying 8 different 7 digit numbers?

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How many four-digit combinations can you get using the numbers 0 to 9?

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