There are 75 multiples of 12 between 100 and 1000.
There are 2000 4-digit numbers that are multiples of 5, so, instead of listing them all, it is equally valid to say: Any4-digit number whose final digit is either a 5 or a 0 is a multiple of 5. Get Right? :P
The number 1234567890 can create about 39 of 40 4 digit numbers.
Any 3 out of 4 = 4. Each set can be arranged 6 ways so 24 different numbers.
You would get 4!/2! = 12 combinations.
There are 75 multiples of 12 between 100 and 1000.
There are 2000 4-digit numbers that are multiples of 5, so, instead of listing them all, it is equally valid to say: Any4-digit number whose final digit is either a 5 or a 0 is a multiple of 5. Get Right? :P
0, 2, 4, 6, 8
There are 720 of them. The three digit counting numbers are 100-999. All multiples of 5 have their last digit as 0 or 5. There are 9 possible numbers {1-9} for the first digit, There are 10 possible numbers {0-9} for each of the first digits, There are 8 possible numbers {1-4, 6-9} for each of the first two digits, Making 9 x 10 x 8 = 720 possible 3 digit counting numbers not multiples of 5.
-4
There are 13 two-digit multiples of 7.
even numbers, specifically the last digit is 0, 2, 4, 6, or 8.
24
17
20, 40, 60, 80, 100, 120, 140, 160, 180, 200 . . .
3 digit numbers are lessthan 4 digit numbers
There are 2941 4-digit numbers such no two of its digits differ by 1.