There is no seven-digit number that has a sum of 5. The smallest seven-digit number is 1,000,000, which already has a sum greater than 5.
5
Six of them.
There are 5 numbers which can make the 3 digit numbers in this example. Therefore each digit in the 3 digit number has 5 choices of which number can be placed there. Therefore number of 3 digit numbers = 5 x 5 x 5 = 125
100 times greater because 100*0.5 = 50
There is no seven-digit number that has a sum of 5. The smallest seven-digit number is 1,000,000, which already has a sum greater than 5.
5
105 - is the smallest tree-digit number that has the digit 5
Six of them.
Any number that ends with the digit 5 is divisible by 5.Any number that ends with the digit 5 is divisible by 5.Any number that ends with the digit 5 is divisible by 5.Any number that ends with the digit 5 is divisible by 5.
There are 5 numbers which can make the 3 digit numbers in this example. Therefore each digit in the 3 digit number has 5 choices of which number can be placed there. Therefore number of 3 digit numbers = 5 x 5 x 5 = 125
How many two digit number are divisible by 5
A three digit number cannot be divisible by a 5 digit number - in any base.
It depends on how many digit you are choosing from.
The smallest, positive 5-digit whole number is 10,000
18 of them.
There are 18 numbers with 2 digits that are divisible by 5. First 2 digit number is 10 → 10 ÷ 5 = 2 → first 2 digit number divisible by 25 is 5 × 2 Last 2 digit number is 99 → 99 ÷ 5 = 19 4/5 → last 2 digit number divisible by 5 is 5 × 19 → There are 19 - 2 + 1 = 18 numbers with 2 digit divisible by 5.