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How many 5 letters can be formed out of the letters of the word mathematics of repetition is not allowed?
Wiki User
∙ 10y ago
There are eight (8) different letters in that word, so that's the number of
letter choices you have in each 5-letter group without repetition.
The number of different 5-letter "words" is (8 x 7 x 6 x 5 x 4) = 6,720 .
(They don't necessarily mean anything. They're just distinct sequences
of 5-letters each, like Morse-code random practice groups.)
Wiki User
∙ 10y ago
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How many 5 digit number can be formed using the digits 02345when repetition is allowed such that the number formed is divisible by 2 or 5 or both?
There are 2000 such numbers.
How many 3 digit numbers can be formed from 6 single digit numbers if repeats are allowed?
if the repetition is allowed the there is 6*6*6 possible ways = 216
How many odd numbers less than 100 can be formed by using the digits 0 3 5 7 when repetition fo digits is not allowed?
9 odd numbers less than 100 can be formed. They are: 3,5,7,35,37,53,57,73 and 75.
How many 3 digit numbers can be formed from digits 0 1 2 3 4 5 6 7 8 9 and what are the results?
If repetition is allowed and leading zeros are allowed, then you have 000 to 999, which is 1,000 possibilities (I will not list them here). If no leading zeros are allowed, then you have 100 through 999, so there are 900 possibilities. If there are other restrictions, such as no repetition, then I'll refer you to the related link at MathsIsFun.com
How many 5 digit numbers can be formed using the digits 0 1 2 3 4 5 6 7 8 9 if no repetition is allowed?
If the first number can not be zero then it is 9x9x8x7x6=27,216 If the first number can be zero then it would be 10x9x8x7x6=41,160
What is the answer for the number of 3 letter words with or without meaning that can be formed out of the letters of the word LOGARITHMS if repetition of the letters is not allowed?
It is 720.
How many 3 digit numbers are formed from 1234567?
If repetition is allowed . . . . . 343 If repetition is not allowed . . . . . 210
How many 3 digit numbers can be formed from the digits 1234?
64 if repetition is allowed.24 if repetition is not allowed.
How many different positive integers less than 2000 can be formed by using digits 123 and 4?
64 if repetition is allowed, 6 otherwise.64 if repetition is allowed, 6 otherwise.64 if repetition is allowed, 6 otherwise.64 if repetition is allowed, 6 otherwise.
How many subsets are there in a set formed from the letters of the word mathematics?
In a set, as it is usually defined, elements can't be repeated. "Mathematics" has 8 distinct letters, so your set would have 8 letters. The number of possible subsets (this includes the empty set, and the set itself) is two to the power 8.
How many 13 digit numbers are possible by using the digits 12345 which are divisible by 4 if repetition of digits is not allowed?
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
How many 5 digit number can be formed using the digits 02345when repetition is allowed such that the number formed is divisible by 2 or 5 or both?
There are 2000 such numbers.
How many 3 digit numbers can be formed with set 15678 if repetition is allowed?
There are 5*5*5 = 125 such numbers.
How many 3 digit numbers can be formed from 6 single digit numbers if repeats are allowed?
if the repetition is allowed the there is 6*6*6 possible ways = 216
How many even 3-digit numbers can be formed from digits 1 3 5 7 9 repetition allowed?
125 There are five choices for each of the three digits (since repetition is allowed). So there are 5*5*5=125 combinations.
How many 3 digits odd numbers can be formed from the digits 1 2 3 4 and 5 if repetition is not allowed?
125
What is the sum of all the four digit numbers formed using the digits 0 1 2 and 3 if repetition is allowed?
It is 415968.
