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Q: How many 5 number combinations are there in the numbers 4 6 11?
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How many combinations of 2 are there in 11 numbers?

There are 11C2 = 11*10/(2*1) = 55 combinations.


How many combinations of 6 can you make with 11 numbers without repeating a combination or number twice?

The number of combinations, denoted by 11C6 is 11!/[6!*(11-6)!] = 11*10*9*8*7/(5*4*3*2*1) = 462


What 3 odd numbers create 43?

There are several combinations of odd numbers that add up to 43. For example, 3 + 29 + 11 is equal to 43, so is 5 + 27 + 11, and many more. In fact, if you allow negative numbers, you have an infinite number of combinations.


How many combinations are there to equal 45 using the numbers 5 and 10 and 15?

There are 11.There are 11.There are 11.There are 11.


How many four digit combinations are there in the numbers 1 to 12?

There are 12C4 4 NUMBER combinations. And that equals 12*11*10*9/(4/3/2/1) = 495 combinations. However, some of these, although 4 number combinations consist of 7 digits eg 1, 10, 11, and 12. Are you really sure you want 4-DIGIT combinations?


How many combinations of 12 numbers are there in 24?

There are 24C12 = 24*23*...*13/(12*11*...*1) = 2,704,156 combinations.


How many number combinations for the numbers 1 through four?

1 and 11 and 21 and 31 and 42 and 12 and 22 and 32 and 43 and 13 and 23 and 33 and 44 and 14 and 24 and 34 and 416 combinations


How many combinations of numbers can you get with 1189 with one repeating?

You can get only four combinations: They are: 11, 118, 119 and 1189. In a combination, the order of the digits does not matter.


How many four combinations are there using numbers 0-11?

11


How many combinations of 8 numbers are there in 56 numbers?

Assuming you meant how many combinations can be formed by picking 8 numbers from 56 numbers, we have:(56 * 55 * 54 * 53 * 52 * 51 * 50 * 49)/8! = (7 * 11 * 3 * 53 * 13 * 51 * 25 * 7) = 1420494075 combinations. (Also equal to 57274321104000/40320)


What are all of the number combinations for the numbers 0 through 9?

If you can use the same number twice, such as 11 or 22, then there are 100 possible numbers (00, and 01-99). If you can not use the same number twice, the answer is 90.


How many 4 number combinations can you make with numbers from1 to 13 with out the numbers repeating?

(13 x 12 x 11 x 10)/(4 x 3 x 2 x 1) = 715 of them