Prob(at least one 5 in 120 throws) = 1 - prob(no 5s in 120 throws)= 1 - (5/6)120= 0.999 999 999 69 = almost 1.Prob(at least one 5 in 120 throws) = 1 - prob(no 5s in 120 throws)= 1 - (5/6)120= 0.999 999 999 69 = almost 1.Prob(at least one 5 in 120 throws) = 1 - prob(no 5s in 120 throws)= 1 - (5/6)120= 0.999 999 999 69 = almost 1.Prob(at least one 5 in 120 throws) = 1 - prob(no 5s in 120 throws)= 1 - (5/6)120= 0.999 999 999 69 = almost 1.
5 goes into 188 37.6 times. (37 times with a remainder of 3.)
21 5s
It goes 120/5 = 24 times
10 goes into 120 12 times
4 goes 30 times into 120, with nothing left over. 4x30=120.
Rubidium has one 5s electron.
It goes: 480/4 = 120 times
7 goes into 120 exactly 17 times.
Exactly 120 times.
17 with 1 remaining 120 - 1 = 119 = 7 x 17
1,2,3,4,5,6,8,10,12,15,20,24,30,40,60 go into 120