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Q: How many 8 inch by 8 inch tiles in a 4 by 6 ft area?

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An area of 50 square feet requires a minimum of four 48-inch tiles.

Nine square feet is equal to 3.24 20-inch tiles.

4-ft x 6-ft = 24 square feet 18-in x 18-in = 1.5-ft x 1.5-ft = 2.25 square feet 24/2.25 = 10 2/3 It would take 102/3 tiles to cover that area. Depending on the shape of the area, some of the tiles may have to be cut up to fit it.

142.22 tiles First, calculate the number of square inches you need by converting : 320 ft²*144 in² 1 ft²=46,080 in² Second, determine the area of the tiles: 18in * 18in = 324 in² Lastly, divide the total area by the area of the tile to determine the number you need: 46,080 in² / 324 in² = 142.22 tiles

Length (ft) x Width )ft) = Area (sq ft); 8 x 6 = 48 sq ft; Assuming the 6-inch tiles are square, then 4 tiles = 1 sq ft Multiply 48 sq ft x 4 tiles per sq ft to determine: 48 x 4 = 192 tiles

A 4 inch by 2 inch tile will have an area of 1/18 ft2. A 3 ft x 6 ft area will occupy 18 ft2, so in theory you could get 18x18=324 tiles into that area. From a practical standpoint, there will be space between the tiles for grout. To get a more accurate answer, you need to add the width of the grout to the height and width of the tiles, so, for example, you used a 1/4 inch grout gap, your tiles would be effctively about 4.25 x 2.25 inches and occupy about 0.0664 ft2 each. Using this as the area of a tile, you would be able to get about 271 tiles into an area that is 3 ft x 6 ft. bigger gaps will mean less tiles, smaller gaps will mean more, but not more than 324.

LXW is the formula for area so it's 4X6=?? Then its 12X12 tiles = 1 sq ft each so looks a lot like 24 tiles

247.1

6 x 24 inch tile = 144 sq in = 1 sq ft 400/1 = 400 tiles

Floor area = 12 ft x 18 ft = 216 square feet. There are 4 six-inch square tiles needed for each square foot, so 864 tiles are needed.

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