4 of them.
4
2 Except that the fact that the figure is given as 3300 g instead of 3.3 kg suggests that the trailing 0s are significant.
Six - zeros between significant digits are significant.
There are 4 significant figures in 9.0170. They are the 9, 1, 7, and the second 0.
If the scale is calibrated in tenths of a kilogram I do not see how you can estimate to the nearest two hundredths of a kilogram! The calibration allows you to measure mass (in kilograms) to 1 decimal place. For masses less than 10 kg, that mean 2 significant figures. For masses of 10 kg or more but less than 100 kg, you can give the information to 3 sf and for masses of 100 kg or more, 3 sf.
0.20 Kg or 200 g Specific heat is 4186 J * Kg * Change in temperature of either K or C Thus Kg = 47000 J / (4186 J * 55 K) = .20 Kg The answer to four digits is 0.2041, but the amount of joules you have only has two significant figures, so the final answer would only have two significant figures.
How many significant figures are in 13001kg
5 significant figures.
There are 2 significant figures in this mass.
There are 2 significant figures in this measurement.
There are 5 significant figures in 6.0050
There are 2 significant figures in this measurement.
There are 2 significant figures in this measurement.
5 significant figures.
4 of them.
one of them.
1 of them.
3