To answer this question the voltage of the ballast must be stated and the type of lamp in the fixture.
Max amps would be 1000 divided by 120.
1KW is 1000w. one watt is equals to product of volt and current. current=watt/volt =1000/240 =4.1667 amps
Power(Watts) = I (Amps) x E(Voltage) PIE rule. so 1000 = I x 240. 1000/240 = 4.16667 amps.
About 1.66 amps at 120 volts Ballasts have stickers on them that tell you the exact amps per the voltage that you are running
figure out how many amps are in a watt and x by 40
Max amps would be 1000 divided by 120.
It will power two 400 watt lamps.
To answer this question the voltage needs to be known.
1KW is 1000w. one watt is equals to product of volt and current. current=watt/volt =1000/240 =4.1667 amps
~9.1 Amps P [W]= E [V] x I [A]
Power(Watts) = I (Amps) x E(Voltage) PIE rule. so 1000 = I x 240. 1000/240 = 4.16667 amps.
About 1.66 amps at 120 volts Ballasts have stickers on them that tell you the exact amps per the voltage that you are running
figure out how many amps are in a watt and x by 40
Yes, if that is all that is on the circuit.
If your generator is rated at 1000 watts continuous......and you are using 120V.....available amps are 1000/120 =8.3 .
5 amps
No, you can not use a 150 watt high pressure sodium bulb with a 70 watt ballast.