0
8 (assuming unsigned numbers - i.e., you don't reserve a bit for the sign).
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What is the minimum number if binary bits required to represent the decimal number 250?
8
What is the smallest decimal number that can be stored using 8 bits?
0.0000001
How many bits are needed in order to represent the decimal values from 0 to 15?
4 bits. 24 = 16, so you have 16 different combinations.4 bits. 24 = 16, so you have 16 different combinations.4 bits. 24 = 16, so you have 16 different combinations.4 bits. 24 = 16, so you have 16 different combinations.
What is the Largest decimal number that can be represented using 16 bits in BCD?
65,535
How many binary bits are needed to represent decimal number 231?
At least 8 bits are needed to represent the number 231. 231 ÷ 2 = 115 r 1 115 ÷ 2 = 57 r 1 57 ÷ 2 = 28 r 1 28 ÷ 2 = 14 r 0 14 ÷ 2 = 7 r 0 7 ÷ 2 = 3 r 1 3 ÷ 2 = 1 r 1 1 ÷ 2 = 0 r 1 → 231 is 1110 0111 in binary and has 8 binary digits. Thus 231 can be represented in 8 bits, but if more are provided, eg 16, it can still be represented (in 16 bits it would be 0000 0000 1110 0111, unless there is a binary point, with say 8 bits after it, then 231 would be 1110 0111 . 0000 0000).
How many binary bits are needed to represent decimal number 21?
5
How many bits are needed to represent decimal 200?
8 bits if unsigned, 9 bits if signed
How many bits are needed to represent decimal value ranging from 0 to 12500?
how many bits are needed to represent decimal values ranging from 0 to 12,500?
What is the minimum number of bits required to represent the decimal 1000?
9 bits
how many bits are needed to represent decimal values ranging from 0 to 12,500?
1200
How many bits need to represent the decimal number 200?
8
What is the minimum number if binary bits required to represent the decimal number 250?
8
How many bits are required to represent 32 digit decimal number?
103
Four bytes can represtent a decimal number between 0 and?
Four bytes represent 32 bits. 32 bits represent 4,294,967,296 possibilities.
What is the minimum number of bits required to represent the following decimal number 101000?
17 bits would allow a value up to 131071.
How may bits are needed to represent the decimal number 200?
log2 200 = ln 200 ÷ ln 2 = 7.6... → need 8 bits. If a signed number is being stored, then 9 bits would be needed as one would be needed to indicate the sign of the number.
Number of bits to represent the binary equivalent of the decimal 62?
6 bits 111110 = 32 + 16 + 8 + 4 + 2 + 0
